Final answer:
If 0.0650 moles of barium hydroxide are added to water, 0.1300 moles of OH⁻ would be produced since barium hydroxide dissociates completely in water, releasing two moles of OH⁻ for every mole of barium hydroxide.
Step-by-step explanation:
When 0.0650 moles of barium hydroxide (Ba(OH)2) are added to water, 0.1300 moles of OH− ions would be produced.
Barium hydroxide is a strong base and dissociates completely in water according to the following balanced equation:
Ba(OH)2 → Ba2+ + 2OH−
Since one mole of barium hydroxide produces two moles of hydroxide ions, you simply multiply the number of moles of barium hydroxide by 2 to find the number of moles of hydroxide ions produced:
0.0650 moles Ba(OH)2 × 2 moles OH−/mole Ba(OH)2 = 0.1300 moles OH−