Final answer:
The question asks for the probability of randomly selecting a four-person committee of Canadians from a pool of Canadians and Americans. This is a high school level mathematics problem, specifically involving combinations in probability and combinatorics.
Step-by-step explanation:
The question involves randomly selecting a four-person committee consisting entirely of Canadians from a pool of 15 Americans and 11 Canadians. This is a problem of probability and combinatorics, fields within mathematics that deal with the likelihood of different outcomes and the counting of arrangements respectively. Since we are selecting all members of the committee from one subgroup (Canadians) without regard to order, we use combinations.
To find the number of ways to select a four-person committee from the 11 Canadians, we calculate the combination of 11 Canadians taken 4 at a time, usually represented as 11C4 or C(11, 4). The formula for combinations is:
C(n, k) = n! / (k!(n-k)!)
where 'n' is the total number of items to choose from, 'k' is the number of items to choose, and '!' represents the factorial of a number.
In this case, we would calculate 11! / (4!(11-4)!) to get the number of combinations possible for the committee.