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An apple that weighs 2.0 n falls vertically downward from rest for 1.7 s .

what is the change in the apple's momentum per second?

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Final answer:

To find the change in momentum per second of an apple falling vertically downward, calculate the final velocity using the equation v = g * t and plug it into the formula change in momentum per second = (0.2 kg * final velocity - 0) / 1.7 s.

Step-by-step explanation:

To find the change in momentum per second of an apple that falls vertically downward, we'll use the formula: change in momentum per second = (final momentum - initial momentum) / time.

The initial momentum of the apple is zero since it starts from rest, and the final momentum can be found using the equation: momentum = mass * velocity. Since the mass of the apple is not given, we'll assume it to be 0.2 kg. We know that the change in time is 1.7 s. Plugging in the values, we have: change in momentum per second = (0.2 kg * final velocity - 0) / 1.7 s. Calculating the final velocity:

final velocity = g * time, where g is the acceleration due to gravity (9.8 m/s²). Plugging in the values, we get: final velocity = 9.8 m/s² * 1.7 s = 16.66 m/s. Now plugging the final velocity back into the initial equation:

change in momentum per second = (0.2 kg * 16.66 m/s - 0) / 1.7 s.

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