Question

For the production of ammonia from its elements, 3H₂(g)+N₂(g)→2NH₃(g),

ΔH = -22 kcal/mol (-92 kJ/mol).

How much energy (in kilocalories and kilojoules) is released in the production of 0.650 mol of NH₃?

Answer 1

The production of 0.650 mol of NH₃ releases 29.9 kJ (or 7.15 kcal) of energy, based on the reaction's enthalpy change.

Step-by-step explanation:

To calculate the energy released in the production of 0.650 mol of NH₃, we can use the reaction's enthalpy change (ΔH). The given balanced chemical equation for the production of ammonia from its elements is:

3H₂(g) + N₂(g) → 2NH₃(g)

From this equation, we know that formation of 2 moles of NH₃ releases 92 kJ (or 22 kcal) of energy. Since the question asks about 0.650 moles, we can set up a proportion to find the energy released:

(92 kJ / 2 mol NH₃) × (0.650 mol NH₃) = 29.9 kJ

(22 kcal / 2 mol NH₃) × (0.650 mol NH₃) = 7.15 kcal

Therefore, the production of 0.650 mol of NH₃ releases 29.9 kJ (or 7.15 kcal) of energy.