Question

An air mass of volume 6.5 x 10⁵ l starts at sea level, with an unknown pressure. it rises up a mountain where the pressure is 622 mm hg and has a volume of 9.8 x 10⁵ l. assuming no change in temperature, what was the original pressure of the air mass?

Answer 1

To find the original pressure of the air mass, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional. Plugging in the given values, the original pressure is calculated to be 937 mmHg.

Step-by-step explanation:

To find the original pressure of the air mass, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional, assuming no change in temperature. We can set up the equation:

P1V1 = P2V2

where P1 is the original pressure, V1 is the original volume, P2 is the pressure at the top of the mountain, and V2 is the volume at the top of the mountain.

Plugging in the given values:

(P1)(6.5 x 105 L) = (622 mmHg)(9.8 x 105 L)

Simplifying the equation:

P1 = (622 mmHg)(9.8 x 105 L) / (6.5 x 105 L)

Calculating the answer:

P1 = 937 mmHg