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You fill a balloon with 2.50 moles of gas at 24°c at a pressure of 1.78 atm. what is the volume of the balloon?

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Final answer:

Using the Ideal Gas Law, we find that a balloon filled with 2.50 moles of gas at 24°C and a pressure of 1.78 atm has a volume of approximately 34.82 liters.

Step-by-step explanation:

To find the volume of the balloon filled with gas, we can use the Ideal Gas Law which can be stated as PV = nRT, where:

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the amount of substance of the gas (in moles),
  • R is the ideal, or universal, gas constant,
  • T is the temperature of the gas (in Kelvin).

Given that:

  • P = 1.78 atm,
  • n = 2.50 moles,
  • T = 24°C = 297 K (since we must convert to Kelvin: T(K) = T(°C) + 273.15),
  • R = 0.0821 L·atm/K·mol (universal gas constant).

Inserting these values into the Ideal Gas Law equation:

(1.78 atm) x V = (2.50 mol) x (0.0821 L·atm/K·mol) x (297 K)

Now isolate V for the volume:

V = ((2.50 mol) x (0.0821 L·atm/K·mol) x (297 K)) / (1.78 atm)

After calculating, the volume V ≈ 34.82 liters.

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