Question

Place the following in order of increasing standard molar entropy.

H₂O(l) H₂O(g) H₂O(s)
O H₂O(g), H₂O(s), H₂O(l)
O H₂O(l), H₂O(s), H₂O(g)
O H₂O(g), H₂O(l), H₂O(s)
O H₂O(s), H₂O(l), H₂O(g)

Answer 1

The correct order from lowest to highest standard molar entropy for water in different states is solid (H₂O(s)), followed by liquid (H₂O(l)), and then gas (H₂O(g)).

Step-by-step explanation:

To place H₂O(l), H₂O(g), and H₂O(s) in order of increasing standard molar entropy, we need to consider the molecular disorder and freedom of movement in each state of matter. Solid water (ice) has its molecules arranged in a highly ordered structure, hence, possessing the lowest entropy.

Liquid water has more disorder, as its molecules can move more freely compared to the solid, resulting in higher entropy. Lastly, water vapor (gaseous state) has the highest entropy because its molecules are completely free to move and occupy the available space without any fixed arrangements.

Therefore, the correct order from lowest to highest entropy is: H₂O(s), H₂O(l), H₂O(g).