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A toy car has a spring launch system. the toy is pulled back to load the spring, then released. the car then travels at speed along its track. what is the correct energy transfer for this process, assuming no energy is lost?

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Final answer:

The energy transfer for a toy car with a spring launch system involves transforming the potential energy in the spring into kinetic energy, which may then be partially converted into gravitational potential energy as the car moves up a slope, based on the conservation of mechanical energy principle.

Step-by-step explanation:

The question revolves around the concept of energy transfer in a toy car with a spring launch system. This involves understanding how the potential energy stored in the compressed spring is converted into the kinetic energy that propels the toy car along its track, and how that kinetic energy may then be converted into gravitational potential energy as the car moves up a slope.

Assuming no energy is lost, the correct energy transfer process for the toy car when it is released from the compressed spring is as follows: The potential energy in the compressed spring (PEi) is completely transformed into kinetic energy (KEf) when the spring is released. As the car goes up the slope, some of the kinetic energy is converted into gravitational potential energy (PEf) because the car gains altitude.

Expressed with energy conservation formula: PEi = KEf + PEf, where:

  • PEi is the initial spring potential energy
  • KEf is the kinetic energy of the car immediately after release
  • PEf is the gravitational potential energy at a certain altitude on the slope

It is important to note that in a real scenario, some energy would be lost due to friction and air resistance, but for the purposes of this question, those factors are ignored.

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