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A water treatment plant is treating water at a flowrate of 0.1 m³/s. The sedimentation basin has 50 m of weir. The weir loading rate (m³/d-m) is most

nearly:

User Voondo
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Final answer:

The weir loading rate at the water treatment plant, treating water at a flowrate of 0.1 m³/s with a 50 m long weir, is calculated to be approximately 172.8 m³/d-m.

Step-by-step explanation:

The question is related to the weir loading rate at a water treatment plant, which is an important concept in the field of environmental engineering. To calculate the weir loading rate, you need to know the flow rate of the water and the length of the weir. The flow rate provided is 0.1 cubic meters per second (m³/s), and the length of the weir is 50 meters.

To find the weir loading rate in cubic meters per day per meter of weir (m³/d-m), we use the following steps:

  1. Convert the flow rate to cubic meters per day (m³/d): 0.1 m³/s × 86,400 seconds/day = 8,640 m³/d.
  2. Divide by the length of the weir to get the loading rate: 8,640 m³/d ÷ 50 m = 172.8 m³/d-m.

Therefore, the weir loading rate at this water treatment plant is approximately 172.8 m³/d-m.

User Wyatt Barnett
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