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A 50.00 g sample of a solution of naphthalene [C₁₀ H₈(s)] in benzene [C₆H₆(I)] has a freezing point of 4.45C. Calculate the mass percent C₁₀Hg and boiling point of this solution. [Kf 5.12 Kg mol⁻¹ C; Kb = 2.53 Kg mol⁻¹ C]

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Final answer:

Mass percent and boiling point of the naphthalene solution cannot be calculated with the information given, as the freezing point depression of the solution and the boiling point elevation constant for benzene (Kb) are missing which are critical for solving colligative property problems.

Step-by-step explanation:

The subject of this question is Chemistry, specifically focusing on the freezing point depression and boiling point elevation properties in the field of solutions and colligative properties. The grade level here is High School.

Mass percent of C10H8 and the boiling point cannot be calculated with the provided data; key information such as the freezing point depression of the solution and the boiling point elevation constant for benzene are missing.

To calculate the mass percent and boiling point of a solution, you typically use the colligative properties of freezing point depression and boiling point elevation which are dependent on the molality of the solution and the solute's molar mass. However, to compute these values for the naphthalene in benzene solution, we need additional information including the depression in freezing point from the pure solvent (benzene) caused by the solution and the boiling point elevation constant for benzene (Kb), which is not given.

Once these values are known, the Van't Hoff factor (which is 1 for non-electrolytes such as naphthalene) is also taken into account to calculate the molality and from there the molar mass and ultimately the mass percent of the solute can be found. The boiling point of the solution is calculated by adding the product of the solution's molality, the boiling point elevation constant (Kb), and the Van't Hoff factor to the normal boiling point of the solvent (benzene).

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