Question

A wind up radio uses two rechargeable cells, each capable of storing 1800 coulombs of charge. if the owner recharges the cells for 5 minutes, how much charge will be stored in the cells if the total current flowing to the cells is 1.5a?

Answer 1

To find out how much charge is stored in the cells of a wind-up radio after recharging for 5 minutes with a current of 1.5 A, one multiplies the current by the time in seconds, resulting in 450 coulombs of charge.

Step-by-step explanation:

The question at hand involves using the physics concept of charge and current to determine how much charge is stored in the rechargeable cells of a wind-up radio. The amount of charge (Q) stored in the rechargeable cells can be calculated using the relationship Q = I * t, where I is the current and t is the time.

With a current (I) of 1.5 A flowing for 5 minutes (300 seconds), the charge stored (Q) in the cells can be calculated as 1.5 A * 300 s, which equals 450 C. This indicates that when recharging for 5 minutes at a total current of 1.5 A, 450 coulombs of charge will be stored in the cells.