Final answer:
To determine the arrival time in Multan for a train that left Karachi at 09:10 and traveled for 15 hours, we add the duration to the departure time, resulting in an arrival time of 00:10 hours. The example of the Zephyr train is used to illustrate how to calculate average speed, yielding 124.8 km/h or 34.69 m/s.
Step-by-step explanation:
The question deals with calculating the arrival time of a train given the departure time and duration of travel. The train left Karachi at 09:10 hours and reached Multan 15 hours later. To find the arrival time, we add 15 hours to the departure time.
Starting with the departure time of 09:10 hours, adding 15 hours gives us 24:10 hours. However, the time format needs to be in a 24-hour cycle, so we convert 24:10 hours to the next day. That means the time is 00:10 hours on the next day. Thus, the train reached Multan at 00:10 hours, or 10 minutes past midnight the following day.
- Start with the initial time: 09:10 hours.
- Add the duration of the journey: 09:10 + 15:00 = 24:10 hours.
- Convert to the correct format for a 24-hour clock: 24:10 becomes 00:10 hours.
The average speed calculation of the Zephyr train mentioned in the reference information provides an example of how to calculate average speed in two units of measure. The Zephyr traveled 1633.8 km in 13 hours, 4 minutes, and 58 seconds.
To find its average speed, we first convert the time to hours:
13 hours + 4 minutes/60 + 58 seconds/3600 = 13.083 hours.
Average speed in km/h is then calculated by distance divided by time:
1633.8 km / 13.083 hours ≈ 124.8 km/h.
To convert to meters per second (m/s), we use the formula:
1 km/h = 0.27778 m/s,
so 124.8 km/h ≈ 124.8 * 0.27778 m/s ≈ 34.69 m/s.
The Zephyr's average speed was approximately 124.8 km/h or 34.69 m/s.