Final answer:
To calculate the magnetic flux through one winding of the solenoid, first calculate the magnetic field inside the solenoid, then find the cross-sectional area, and multiply them to get the magnetic flux.
Step-by-step explanation:
The question is asking to calculate the magnetic flux through one winding of a solenoid when a given current is passing through it. The solenoid has specific dimensions and number of turns per unit length. The magnetic flux Φ through a solenoid can be calculated by first finding the magnetic field B using Ampère's Law, and then using the formula Φ = B × A, where A is the cross-sectional area of the solenoid.
Calculation Steps
- Calculate the magnetic field B inside the solenoid using B = μ0 × n × I, where μ0 is the permeability of free space (4π × 10-7 H/m), n is the number of turns per unit length, and I is the current.
- Find the cross-sectional area A of the solenoid using A = π × (d/2)2, where d is the diameter of the solenoid.
- Compute the magnetic flux Φ through one winding of the solenoid by multiplying the magnetic field B by the cross-sectional area A.
To find the answer, each of these steps will be applied using the provided dimensions and current of the solenoid in question. By substituting n = 150 turns/cm, I = 0.259 A, and diameter d = 0.847 cm into the formulas, we can calculate the magnetic field B and then the magnetic flux Φ through one of the windings of the solenoid.