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A wave has amplitude of 0.35 m, a frequency of 1.05×10⁶ Hz, and travels in the positive x direction at the speed of light, 3.00×10⁸ m/s. Determine the equation that correctly represents this wave.

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Final answer:

The equation representing the wave with a given amplitude, frequency, and speed of light is y(x,t) = 0.35 m · sin((2.20×10^-2 rad/m)x - (6.58×10^6 rad/s)t), where the wavelength is 285.71 m.

Step-by-step explanation:

To determine the equation that correctly represents a wave with an amplitude of 0.35 m, a frequency of 1.05×106 Hz, and a speed of light (3.00×108 m/s), we first need the wavelength λ. Using the relationship c = fλ, we can find the wavelength by rearranging the equation to λ = c/f.

The wavelength (λ) can be calculated as:

λ = · (3.00×108 m/s) / (1.05×106 Hz) = 285.71 m

The wave equation is generally given as y(x,t) = A sin(kx - ωt), where A is the amplitude, k is the wave number, and ω is the angular frequency. Since k = 2π/λ and ω = 2πf, we can substitute the known values to find these parameters.

k = (2π) / (285.71 m) ≈ 2.20×10-2 rad/m

ω = (2π) · (1.05×106 Hz) = 6.58×106 rad/s

Finally, the wave equation for this electromagnetic wave traveling in the positive x direction is:

y(x,t) = 0.35 m · sin((2.20×10-2 rad/m)x - (6.58×106 rad/s)t)

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