75.2k views
1 vote
A sample of N₂ gas has a volume of 19.0 L at a pressure of 1.50 atm and a temperature of 23° C. What volume, in liters, will the gas occupy at 3.50 atm and 226° C ?

User JamieD
by
7.2k points

1 Answer

3 votes

Final answer:

To find the new volume of N₂ gas at a pressure of 3.50 atm and a temperature of 226° C, convert the original and final temperatures to Kelvin and use the combined gas law rearranged to solve for the final volume.

Step-by-step explanation:

The question pertains to the calculation of the volume of N₂ gas at different conditions using the ideal gas law. To find the new volume of the gas at 3.50 atm and 226° C, you can use the combined gas law which is derived from the ideal gas law: P1V1/T1 = P2V2/T2. Since we are given the volume, pressure, and temperature at two different states, we can rearrange the formula to solve for the unknown V2 (final volume).

First, we need to convert the temperatures from degrees Celsius to Kelvin by adding 273.15. Therefore, T1 = 23° C + 273.15 = 296.15 K and T2 = 226° C + 273.15 = 499.15 K. Now we can plug in the known values and solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1) = (1.50 atm * 19.0 L * 499.15 K) / (3.50 atm * 296.15 K)

Carrying out the calculation will give you the new volume V2 in liters.

User Agomcas
by
7.7k points