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A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the length of the calls, in minutes, follows the normal probability distribution. The mean length of time per call was 4.50 minutes and the standard deviation was 0.70 minutes.

What fraction of the calls last between 4.50 and 5.30 minutes?

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Final answer:

To determine the fraction of calls lasting between 4.50 and 5.30 minutes, convert the call times to z-scores and find the associated probabilities.

Step-by-step explanation:

To find the fraction of calls that last between 4.50 and 5.30 minutes, given that call lengths at General Electric Corporate Headquarters follow a normal distribution with a mean of 4.50 minutes and a standard deviation of 0.70 minutes, one would use the standard normal distribution to calculate this probability.

Firstly, we convert the call lengths into z-scores using the formula Z = (X - μ) / σ, where X is the call length, μ is the mean, and σ is the standard deviation. For the lower limit (X = 4.50 minutes), the z-score is (4.50 - 4.50) / 0.70 = 0. For the upper limit (X = 5.30 minutes), the z-score is (5.30 - 4.50) / 0.70 ≈ 1.14.

Next, one would look up these z-scores on a standard normal distribution table or use a statistical software to find the probabilities associated with each z-score. The probability of a call lasting less than the mean is 0.5 (since it's the mean value on a symmetric distribution). To find the probability of a call lasting less than 5.30 minutes, we look up the z-score of 1.14 which gives us a probability of approximately 0.8729.

The difference between these two probabilities, 0.8729 - 0.5, gives us the fraction of calls that last between 4.50 and 5.30 minutes. Thus, approximately 37.29% of calls last between these times.

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