Final answer:
To determine the minimum energy of a photon capable of ejecting electrons from a metal with a given frequency, use the equation E = hv = h * c / λ. To calculate the maximum kinetic energy of the ejected electrons from a metal by light with a given wavelength, use the equation KEmax = hv - Work Function.
Step-by-step explanation:
The minimum energy of a photon capable of ejecting electrons from a metal can be determined using the equation:
E = hv = h * c / λ
where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), v is the frequency, c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. We are given the frequency v₀ = 4.37 x 10^14 s⁻¹, which we can use to find the wavelength λ₀ using the formula v = c / λ.
For the maximum kinetic energy of an ejected electron, we can use the equation:
KEmax = hv - Work Function
where KEmax is the maximum kinetic energy, hv is the energy of the photon, and the Work Function represents the energy required to eject an electron from the metal. Given the wavelength of 235 nm, we can find the energy of the photon using E = hv = h * c / λ.