Question

A boy pulls a car of mass m=20 kg by a cord with constant force F= 200 N at an angle of 37", the normal force in (N) is: O A. None of the above OB. 110 O C. 80 O 0.92

Answer 1

The normal force exerted on a 20 kg car being pulled by a 200 N force at a 37-degree angle is approximately 76 N, calculated by subtracting the vertical component of the pulling force from the car's weight.

Step-by-step explanation:

The question asks for the normal force exerted on a 20 kg car being pulled by a cord with a constant force of 200 N at a 37-degree angle above the horizontal. To find the normal force, we need to consider the vertical forces acting on the car. The gravitational force (weight) acting downward is m x g, where m is the mass (20 kg) and g is the acceleration due to gravity (9.8 m/s2). The vertical component of the pulling force that acts upwards is F sin(θ), where F is the force (200 N) and θ is the angle (37 degrees). The normal force is the force exerted by the surface to support the weight of the car and is equal to the weight minus the vertical component of the pulling force. Using the equation:

N = m x g - F sin(θ),

we calculate the normal force.

Plugging in the values:

N = (20 kg x 9.8 m/s2) - (200 N x sin(37 degrees)) = 196 N - 120 N = 76 N (approximately).

Therefore, the normal force is approximately 76 N.