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A bottle with a volume of 7.5×10⁻³m³ contains 0.0200kg of oxygen gas at 77.0∘C. What is the pressure exerted on the inner walls of the flask by the oxygen gas?

User Ants Aasma
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Final answer:

The pressure exerted on the inner walls of the flask by the oxygen gas is approximately 5.82 Pa.

Step-by-step explanation:

To find the pressure exerted by the oxygen gas, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin. Rearranging the equation, we have:

P = (nRT) / V

Given the volume of the bottle (7.5x10⁻³m³), we can convert it to liters (1m³ = 1000L) which gives us 7.5L. We also have the mass of the oxygen gas (0.0200kg) and the temperature (77.0∘C = 350.15K). To find the number of moles, we need to use the molar mass of oxygen (32.00 g/mol) and calculate:

n = mass / molar mass = 0.0200kg / 0.03200kg/mol = 0.625 mol

Substituting these values into the equation, we get:

P = (0.625 mol x 8.314 J/(mol·K) x 350.15K) / 7.5L = 5.82 Pa

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