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Water witha density of 1185 kg/m³ flows in a horizontal pipe. in one segment of the pipe, the flow speed is v1=5.33 m/s. in a second segment, the flow speed is v2=3.17m/s. what is the difference between pressure p2 in the second segment and the pressure p1 in the first segement

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Final answer:

To find the pressure difference between two segments in the horizontal pipe, Bernoulli's equation is applied, which after substitution and rearrangement shows that the pressure difference is half the product of the density of water and the difference in squares of the velocities in the two segments.

Step-by-step explanation:

To solve the mathematical problem completely regarding the difference in pressure between two segments in a horizontal pipe with water flowing through it, we use Bernoulli's equation because it's an incompressible fluid and the flow is horizontal, meaning the gravitational potential energy term drops out.

Step 1: Write down Bernoulli's equation

Bernoulli's equation is given by:

P + ½ρv^2 = constant,

where P is the pressure, ρ is the density of the fluid, and v is the velocity of fluid flow.

Step 2: Apply Bernoulli's equation to both segments

Since the only change is in the velocity of the fluid, we can set the equation for both points as:

P1 + ½ρv1^2 = P2 + ½ρv2^2,

where the subscript 1 refers to the first segment and the subscript 2 refers to the second.

Step 3: Rearrange the equation to solve for the difference in pressure

By rearranging the equation, we get:

P2 - P1 = ½ρ(v1^2 - v2^2).

Substitute the given values:

P2 - P1 = ½×1185 kg/m^3 ×(5.33 m/s)^2 - (3.17 m/s)^2,

This calculation will then give us the pressure difference between segment 2 and segment 1.

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