Question

A 0.5" x 0.5" square is to be blanked from a 0.050" thick piece of sheet metal. For the sheet material, the yield strength is 40 ksi tensile strength is 65 ksi and fracture strength is 60 ksi. The value of Ac=0.05.

What force in tons will be required to shear all 3 parts simultaneously assuming a flat-bottomed punch?

Answer 1

To calculate the force required to shear a square from a sheet of metal with certain material properties, use the equation F = A * Y, where F is the force, A is the shear area, and Y is the yield strength.

Step-by-step explanation:

The question pertains to calculating the force required to shear a square from a sheet of metal, based on given material properties and dimensions. Since the yield strength of the material is considered for shearing, the equation that relates force (F) to shear area (A) and yield strength (Y) will be used: F = A * Y. The area to be sheared is the perimeter of the square times the thickness of the sheet.

Therefore, A = 4 * 0.5" * 0.050" = 0.1 in². Substituting into the equation along with the yield strength of 40 ksi, the force required is F = 0.1 in² * 40 ksi. To convert ksi to pounds force, we multiply by 1000, and to convert pounds to tons, we divide by 2000 (lbs per ton). The final force required to shear the square is F = (0.1 * 40 * 1000) / 2000 tons = 2 tons.