Final answer:
The function g(x) is equal to -x^2 when x>0 and g(x) is decreasing for x<0. The other statements are false.
Step-by-step explanation:
The function g(x) is defined as:
g(x) = (1/2)^x if x < 0
g(x) = -x^2 if x > 0
- (a) g(x) is equal to (1/2)x when x<0. This statement is false. The function g(x) is not equal to (1/2)x when x<0. It is equal to (1/2)^x.
- (b) g(x) is equal to -x^2 when x>0. This statement is true. The function g(x) is equal to -x^2 when x>0.
- (c) The function g(x) is defined at x=0. This statement is false. The function g(x) is not defined at x=0 because the function is not continuous at x=0.
- (d) g(x) is decreasing for x<0. This statement is true. When x<0, the function g(x) = (1/2)^x, which is a decreasing function as x gets larger and more negative.