Final answer:
The molarity of a calcium acetate solution is found by converting the given mass to moles using the molar mass, then dividing by the volume in liters, resulting in a molarity of 0.05 M.
Step-by-step explanation:
The molarity of a solution containing 3.28 g of Ca(CH₃O₂)₂ in 414 mL is 0.05 M.
To calculate the molarity, we need to convert the mass of the solute Ca(CH₃O₂)₂ to moles and then divide by the volume of the solution in liters. The molar mass of Ca(CH₃O₂)₂ is calculated as follows:
- 40.08 g/mol for Ca
- 2 × (12.01 g/mol for C + 3 × 16.00 g/mol for O + 3 × 1.008 g/mol for H)
Adding these values gives the molar mass of 158.16 g/mol for Ca(CH₃O₂)₂. Next, we convert the mass of the compound to moles:
3.28 g Ca(CH₃O₂)₂ × (1 mol / 158.16 g) = 0.02073 moles. We then convert 414 mL to liters:
414 mL × (1 L / 1000 mL) = 0.414 L.
Finally, we calculate the molarity (M) as follows:
0.02073 moles / 0.414 L = 0.05 M.