Question

Calculate the volume of 2.58 moles of a gas at 37.5 0 c and 95.8 kpa.

Answer 1

Using the Ideal Gas Law, the 2.58 moles of gas at 37.5 °C and 95.8 kPa would occupy a volume of approximately 70.06 liters.

Step-by-step explanation:

To calculate the volume of 2.58 moles of a gas at 37.5 °C (310.65 K) and 95.8 kPa, we can use the Ideal Gas Law, which is PV = nRT, where P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature in kelvins.

First, you'll need to convert the temperature to kelvins by adding 273.15 to the Celsius temperature, which gives us 310.65 K. Next, we use the gas constant R in the units that match the given pressure, which is kPa. Since the pressure is in kPa, we'll use R = 8.314 kPa·L/mol·K.

Inserting the values into the Ideal Gas Law equation:

1. P (pressure) = 95.8 kPa
2. V (volume) = ? L (what we're solving for)
3. n (number of moles) = 2.58 mol
4. R (gas constant) = 8.314 kPa·L/mol·K
5. T (temperature) = 310.65 K

Now we can rearrange the formula to solve for V:

V = (nRT) / P

V = (2.58 mol × 8.314 kPa·L/mol·K × 310.65 K) / 95.8 kPa

V = (67.08 mol·kPa·L·K) / 95.8 kPa

V = approximately 70.06 L

Therefore, 2.58 moles of gas at 37.5 °C and 95.8 kPa would occupy a volume of about 70.06 liters.