Final answer:
The magnitude of the force required to just move the 15kg object along a horizontal surface with a coefficient of friction of 0.1 is 14.7 Newtons.
Step-by-step explanation:
To calculate the magnitude of the force required to just move the 15kg object, we need to consider the force of friction.
The force of friction can be calculated using the formula F = μN, where F is the force of friction, μ is the coefficient of friction, and N is the normal force. In this case, the normal force is equal to the weight of the object, which can be calculated as N = mg, where m is the mass of the object and g is the acceleration due to gravity.
So, the force of friction is F = μmg. Plugging in the given values, we have F = (0.1)(15kg)(9.8 m/s²). Evaluating this expression gives us F = 14.7 N.
Therefore, the magnitude of the force required to just move the 15kg object along a horizontal surface with a coefficient of friction of 0.1 is 14.7 Newtons.
To calculate the magnitude of force required to just move a 15kg object along a horizontal surface with a coefficient of friction of 0.1, we use the formula: Frictional Force (Ff) = Coefficient of Friction (μ) x Normal Force (N).
Since the object is on a horizontal surface, the normal force is equal to the gravitational force on the object, which is its weight (Weight (W) = Mass (m) x Gravity (g), where g is approximately 9.8 m/s2).
So, the normal force on the 15kg object is N = m x g = 15kg x 9.8 m/s2 = 147N. The frictional force that needs to be overcome is then Ff = μ x N = 0.1 x 147N = 14.7N. Therefore, a force of at least 14.7N is required to just start moving the 15kg object.