Question

Assume you have sea water that weighs 64 lb/ft³ and contains 35 parts per thousand (0.035) dissolved salt by weight. how many cubic feet of the sea water would you need to place in an evaporation basin to collect 150 lb of sea salt? (round your answer to the nearest cubic foot.)

Answer 1

To collect 150 lb of sea salt from seawater with a salt concentration of 0.035 by weight, you would need approximately 67 cubic feet of sea water.

Step-by-step explanation:

To solve for the amount of sea water needed to collect 150 lb of sea salt, we use the given concentration of dissolved salt, which is 35 parts per thousand (0.035). First, we determine the amount of sea water needed to get 1 lb of salt:

(1 lb salt) / (0.035 lb salt/lb sea water) = 28.5714 lb sea water

Now, we can calculate the volume of sea water required by using the weight of the sea water per cubic foot:

(150 lb salt) × (28.5714 lb sea water/lb salt) / (64 lb/ft³) ≈ 66.9643 ft³

Therefore, you would need approximately 67 cubic feet of sea water to collect 150 lb of sea salt. This answer is rounded to the nearest cubic foot.