Question

Two charged objects have an attractive force of 10 n. if the charge of both objects increases by a factor of 5, and the distance separating the objects decreases by 1/2, then what is the new force? express your answer to the nearest whole number.

Answer 1

According to Coulomb's law, the new force between the charged objects is 100 N.

Step-by-step explanation:

According to Coulomb's law, the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, if the charge of both objects increases by a factor of 5 and the distance separating them decreases by 1/2, we can calculate the new force as follows:

1. The force between the original charges is 10 N.
2. The charge of both objects increases by a factor of 5. If the original charges were represented as Q1 and Q2, the new charges can be expressed as 5Q1 and 5Q2.
3. The distance separating the objects decreases by 1/2, so the new distance can be expressed as 1/2 of the original distance.
4. Using Coulomb's law, we can calculate the new force:

• Substituting the new charges and distance into the formula: New Force = (k * (5Q1) * (5Q2)) / ((1/2)^2)
• Since the distance is squared, 1/2^2 = 1/4.
• Simplifying the equation, New Force = 100 * (k * Q1 * Q2).

Therefore, the new force between the charged objects is 100 times the original force. Rounding to the nearest whole number, the new force is 100 N.