Question

A 24.7 g sample of an unknown metal, heated to 98.40°C, is transferred to 25.0 mL of H₂O at 21.40°C. The equilibrium temperature is 27.30°C.

What is the specific heat of the metal?

Answer 1

The specific heat of a metal can be determined using the heat transfer equation q = mcΔT. By calculating the expression (100.0g)(4.18 J/g°C)(10.15°C) / (40.0g)(60.15°C - 50.0°C), we can determine the specific heat capacity, c, of the unknown metal.

Step-by-step explanation:

The specific heat of a metal can be determined using the heat transfer equation q = mcΔT, where q is the heat transferred, m is the mass of the metal, c is the specific heat of the metal, and ΔT is the change in temperature. In this case, we know the mass of the metal (40.0g) and the initial and final temperatures (130.0°C and 60.15°C, respectively).

First, we can calculate the heat transferred using the equation q = mcΔT:
q = (40.0g)(c)(60.15°C - 50.0°C)

Since the specific heat capacity of water is given as 4.18 J/g°C, we can substitute this value into the equation:
40.0g(c)(60.15°C - 50.0°C) = (100.0g)(4.18 J/g°C)(60.15°C - 50.0°C)

Solving for c, we find:
c = (100.0g)(4.18 J/g°C)(10.15°C) / (40.0g)(60.15°C - 50.0°C)

By calculating this expression, we can determine the specific heat capacity, c, of the unknown metal.