103k views
0 votes
H(x) = x² - 7x - 81) What are the zeros of the function?

Write the smaller t first, and the larger t second.
smaller x=___
larger x= ____

1 Answer

7 votes

Final answer:

The zeros of the function h(x) are found using the quadratic formula, resulting in approximately -6.16 for the smaller x and 13.16 for the larger x.

Step-by-step explanation:

To find the zeros of the function h(x) = x² - 7x - 81, we use the quadratic formula, which applies to equations of the form ax² + bx + c = 0. For the given function, a = 1, b = -7, and c = -81.

The quadratic formula is given by:

x = (-b ± √b² - 4ac) / (2a)

Plugging in the values from our function:

x = (7 ± √(7² - 4(1)(-81))) / (2(1))

x = (7 ± √(49 + 324)) / 2

x = (7 ± √373) / 2

Since √373 is approximately 19.3132, our two solutions are:

x = (7 + 19.3132) / 2 and x = (7 - 19.3132) / 2

x ≈ 13.1566 and x ≈ -6.1566

Therefore, the smaller x is approximately -6.16 and the larger x is approximately 13.16.

User Osum
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories