Final answer:
The equivalence point (Ve) in the titration of 100 mL of 0.05000 M MES with 0.500 M NaOH is 10 mL.
Step-by-step explanation:
The equivalence point (Ve) is the point in a titration where the amount of titrant added is stoichiometrically equivalent to the amount of analyte being titrated. In this case, the titration is between 100 mL of 0.05000 M MES (analyte) and 0.500 M NaOH (titrant).
To calculate the equivalence point, we need to determine the volume of NaOH required to reach stoichiometric equivalence with MES. One way to do this is to use the equation:
M1V1 = M2V2
where M1 and V1 are the molarity and volume of the analyte, and M2 and V2 are the molarity and volume of the titrant at the equivalence point.
Let's assume that V2 is the volume of NaOH required to reach the equivalence point. Substituting the given values into the equation:
(0.05000 M)(100 mL) = (0.500 M)(V2)
By solving for V2, we find that V2 = 10 mL. Therefore, the equivalence point (Ve) is 10 mL of NaOH.