Question

F(x)=x²+6x+8

What are the zeroes of the function?
Write the smaller x first, and the larger x second
smaller x=___
larger x= ____

Answer 1

The zeroes of the function f(x)=x²+6x+8 are -5 and -1.

Step-by-step explanation:

The zeroes of the function f(x)=x²+6x+8 can be found by setting f(x) equal to zero and solving for x. In this case, we have:

x²+6x+8 = 0

To solve this quadratic equation, we can use the quadratic formula: x = (-b ± √(b²-4ac))/(2a)

Here, a = 1, b = 6, and c = 8. Plugging these values into the quadratic formula, we get:

x = (-6 ± √(6²-4*1*8))/(2*1)

Simplifying further, we have:

x = (-6 ± √(36-32))/(2)

x = (-6 ± √4)/(2)

Therefore, the zeroes of the function are:

smaller x = -3 - √4 = -5

larger x = -3 + √4 = -1