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F(x)=x²-10x-56

What are the zeros of the function?
Write the smaller x first, and the larger x second.
smaller x=___
larger x= ____

User Pierre GM
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1 Answer

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Final answer:

The zeros of the function f(x)=x²-10x-56 are found by applying the quadratic formula. Substituting the values into the formula results in two solutions for x, which are -4 and 14. Hence, the smaller x is -4 and the larger x is 14.

Step-by-step explanation:

The zeros of the function f(x)=x²-10x-56 can be found by solving the quadratic equation where f(x) is set to zero. To find the zeros, we will use the quadratic formula which is x = ∛(-b ± √(b² - 4ac)) / 2a. In our equation, a = 1, b = -10, and c = -56.

Substituting these values into the quadratic formula, we get:

x = ∛(10 ± √((-10)² - 4∗(1)∗(-56)) / (2∗1),

x = ∛(10 ± √(100 + 224)) / 2,

x = ∛(10 ± √(324)) / 2,

x = ∛(10 ± 18) / 2,

which gives us two solutions for x:

x = ∛(10 + 18) / 2 = 14

and

x = ∛(10 - 18) / 2 = -4.

Therefore, the smaller x is -4, and the larger x is 14.

User Unom
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