148k views
1 vote
F(x)=x²-10x-56

What are the zeros of the function?
Write the smaller x first, and the larger x second.
smaller x=___
larger x= ____

User Pierre GM
by
8.3k points

1 Answer

0 votes

Final answer:

The zeros of the function f(x)=x²-10x-56 are found by applying the quadratic formula. Substituting the values into the formula results in two solutions for x, which are -4 and 14. Hence, the smaller x is -4 and the larger x is 14.

Step-by-step explanation:

The zeros of the function f(x)=x²-10x-56 can be found by solving the quadratic equation where f(x) is set to zero. To find the zeros, we will use the quadratic formula which is x = ∛(-b ± √(b² - 4ac)) / 2a. In our equation, a = 1, b = -10, and c = -56.

Substituting these values into the quadratic formula, we get:

x = ∛(10 ± √((-10)² - 4∗(1)∗(-56)) / (2∗1),

x = ∛(10 ± √(100 + 224)) / 2,

x = ∛(10 ± √(324)) / 2,

x = ∛(10 ± 18) / 2,

which gives us two solutions for x:

x = ∛(10 + 18) / 2 = 14

and

x = ∛(10 - 18) / 2 = -4.

Therefore, the smaller x is -4, and the larger x is 14.

User Unom
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories