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Given the logistic model f(x)=(1000)/1+500e⁻⁰.⁴⁰²ˣ, what is the carrying capacity?

User Kettly
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Final answer:

The carrying capacity in the logistic model f(x) = (1000)/(1+500e^-0.402x) is 1000, as this is the value the function approaches as x tends toward infinity indicating the maximum sustainable population size.

Step-by-step explanation:

In the given logistic model f(x) = \(\frac{1000}{1 + 500e^{-0.402x}}\), the carrying capacity can be determined by examining the behavior of the function as x increases without bound. As x approaches infinity, the term 500e^{-0.402x} approaches zero, and the entire denominator approaches 1. Therefore, the function f(x) approaches the value of 1000, which is the carrying capacity of this logistic model.

Carrying capacity (K) is a concept used to describe the maximum population size that a particular environment can sustain indefinitely. In the context of the logistic growth model, when the population size reaches the carrying capacity, growth slows down and the population size stabilizes.

User Astaar
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