Final answer:
The question asks to calculate the volume of xenon at STP given its volume under non-standard conditions. Without the exact final temperature at STP, the exact volume at STP cannot be determined, but the combined gas law can be used to illustrate a hypothetical solution.
Step-by-step explanation:
The question is asking to determine the volume of a gas sample of xenon at standard temperature and pressure (STP), given that its initial conditions are 6.00 liters at 960 mm Hg and 50 degrees. To solve this, one would typically use the combined gas law, which relates the pressure, volume, and temperature of a gas sample. However, since the final temperature is not provided in the question, it's not possible to give an exact answer. But for illustrative purposes, if we assume the intention was to ask for the temperature at 50 degrees Celsius, we can provide a hypothetical solution:
Combined gas law:
(V1 * P1) / T1 = (V2 * P2) / T2
Converting initial temperature to Kelvin (assuming '50' refers to Celsius):
T1 = 50 + 273 = 323 K
STP conditions:
P2 = 760 mm Hg (standard pressure)
T2 = 273 K (standard temperature)
Using the combined gas law and rearranging for V2:
V2 = V1 * P1 * T2 / (P2 * T1)
Plugging in the values:
V2 = 6.00 L * 960 mm Hg * 273 K / (760 mm Hg * 323 K)
V2 = ... (after calculation)
Note: The calculation will yield the volume of xenon at STP once the arithmetic is done, but the actual volume value cannot be determined unless the accurate final conditions are known.