Question

An organ pipe that is open at both ends is 3.2 m long.

what is its fundamental frequency?

Answer 1

To find the fundamental frequency of an organ pipe open at both ends and 3.2 m long, use the formula f = v / (2L) with the speed of sound at 343 m/s, resulting in a fundamental frequency of 53.6 Hz.

Step-by-step explanation:

The question asks for the fundamental frequency of an organ pipe open at both ends, which is 3.2 meters long. In acoustics, the fundamental frequency of an open pipe can be calculated using the formula: f = v / (2L), where f is the fundamental frequency, v is the speed of sound in air, and L is the length of the pipe.

Assuming standard temperature and pressure conditions, the speed of sound in air is approximately 343 meters per second (m/s). Thus, you can calculate the fundamental frequency of the 3.2 m long pipe as follows:

1. First, substitute the length L = 3.2 m.
2. Then, substitute the speed of sound v = 343 m/s.
3. Apply the formula to get: f = 343 m/s / (2 * 3.2 m) = 343 / 6.4 = 53.6 Hz.

Therefore, the fundamental frequency of the organ pipe open at both ends and 3.2 meters long is 53.6 Hz.