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Find the resistance of 240 feet of number 10 copper wire with a cross- sectional area (d²) of 10,380 circular Express the answer to the nearest hundredth. RT= KL/d² R= resistance in ohms. K= specific resistance of copper (10.8) L= length in feet d= diameter in mils 0.24 ohms 2.4 ohms 24.4 ohms 0.024 ohms

User Lucas Dias
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1 Answer

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Final answer:

The resistance of a 240 feet long number 10 copper wire with a cross-sectional area of 10,380 circular mils is approximately 0.25 ohms when calculated using the specific resistance of copper.

Step-by-step explanation:

To calculate the resistance of a 240 feet long number 10 copper wire with a cross-sectional area of 10,380 circular mils (d²), we will use the formula RT = KL/d², where R is the resistance in ohms, K is the specific resistance of copper (10.8), L is the length in feet, and d is the diameter in mils. As the cross-sectional area is given rather than the diameter, we can rearrange the formula to R = KL/A, where A is the area in circular mils.

Now, substituting the values provided into the formula we get:

  • K (specific resistance of copper) = 10.8
  • L (length) = 240 feet
  • A (area) = 10,380 circular mils

Therefore:

R = (10.8 × 240) / 10,380

R = 2592 / 10,380

R = approximately 0.25 ohms

The resistance to the nearest hundredth is 0.25 ohms.

User Jtabuloc
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