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An airline claims that the? no-show rate for passengers booked on its flights is less than? 6%. Of 380 randomly selected? reservations, 18 were? no-shows. Find the? P-value for a test to support the? airline's claim. Round to four decimal places.

A. 0.0746
B. 0.3508
C. 0.1492
D. 0.8508

User Are
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1 Answer

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Final answer:

To support the airline's claim of a no-show rate less than 6%, a hypothesis test is performed. The test statistic is calculated from the observed sample proportion, and the p-value is obtained from a standard normal distribution to compare against the significance level. The final answer is the p-value rounded to four decimal places.

Step-by-step explanation:

Finding the P-Value

To find the p-value for the no-show rate, we first set up the hypothesis test. The null hypothesis (H0) is that the no-show rate is at least 6% (p >= 0.06), and the alternative hypothesis (H1) is that the no-show rate is less than 6% (p < 0.06). The number of no-shows observed is 18 out of 380 reservations, leading to a sample proportion (p-hat) of 18/380.

We then calculate the test statistic using the formula for a one-proportion z-test:

z = (p-hat - p) / sqrt(p*(1-p)/n)
where p-hat is the sample proportion, p is the hypothesized proportion (0.06), and n is the sample size (380).

Our test statistic comes to z = (18/380 - 0.06) / sqrt(0.06*(1-0.06)/380). After calculations, we obtain a z-value. We use this z-value to find the p-value from a standard normal distribution table or software that gives the probability of observing a z-value as extreme as or more extreme than the calculated one.

Since this is a left-tailed test, we find the cumulative probability up to our z-value, giving us the p-value. This p-value will denote the probability of observing a proportion as extreme as or more extreme than our sample proportion, given that the null hypothesis is true.

User Thetoast
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