Question

Which of the following is the correct order of boiling points for BaCl₂, H₂, Co, Hf and Ne?

a) H₂＜Ne＜Hf＜Co＜BaCl₂
b) H₂＜Ne＜Co＜Hf＜BaCl₂
c) H₂＜Hf＜Ne＜Co＜ BaCl₂
d) H₂＜ne＜Co＜ BaCl₂＜Hf
e) BaCl₂＜H₂＜Ne＜Co＜Hf

Answer 1

The correct order of boiling points for BaCl₂, H₂, Co, Hf, and Ne is H₂＜Ne＜Hf＜Co＜BaCl₂.

Step-by-step explanation:

The correct order of boiling points for BaCl₂, H₂, Co, Hf, and Ne is: a) H₂＜Ne＜Hf＜Co＜BaCl₂.

Boiling point is determined by the strength of intermolecular forces between molecules. BaCl₂ is an ionic compound with strong electrostatic interactions, so it has the highest boiling point. H₂ is a diatomic nonpolar molecule with weak London dispersion forces, therefore it has the lowest boiling point.

Ne is a noble gas with only weak London dispersion forces, so it has a slightly higher boiling point compared to H₂. Hf is a transition metal with stronger metallic bonding compared to Co, giving it a higher boiling point. Therefore, the correct order is H₂＜Ne＜Hf＜Co＜BaCl₂.