Final answer:
The gravitational force experienced by a person on Pluto is calculated using the universal law of gravitation with the given masses and the radius of Pluto. The formula F = GmM/r² is used with the values for G (gravitational constant) and the masses and radius provided.
Step-by-step explanation:
To find the magnitude of the gravitational force experienced by a person on the surface of Pluto, we must use Newton's universal law of gravitation. This law states that the gravitational force, F, between two masses is directly proportional to the product of their masses (m and M) and inversely proportional to the square of the distance r between their centers. The formula derived from this law is F = GmM/r², where G is the gravitational constant.
In this problem, the person has a mass of 66.5 kg (which we will call m), Pluto has a mass of 1.25 x 10²² kg (which we will call M), and the diameter of Pluto is given as 2.4 x 10 m, so the radius r, which is half the diameter, will be 1.2 x 10 m. The gravitational constant G is 6.674 x 10⁻¹¹ N·m²/kg². Plugging in these values into the equation, we have:
F = GmM/r² = (6.674 x 10⁻¹¹ N·m²/kg²)(66.5 kg)(1.25 x 10²² kg)/(1.2 x 10 m)²
After performing the calculations, you will find that the force of gravitational attraction experienced by the person standing on the surface of Pluto is the magnitude F.