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Find b and c so that y=−13x²+bx+c has vertex (9,9).
b=
c=

User Derp
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1 Answer

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Final answer:

To find the values of b and c for the quadratic equation y = -13x² + bx + c with a vertex at (9,9), we use the vertex form of a quadratic equation. By substituting the given values into this form and expanding, we determine that b = 234 and c = -1044.

Step-by-step explanation:

To solve the mathematical problem completely and find the values of b and c for the quadratic equation y = -13x² + bx + c that has a vertex at (9, 9), we can use the vertex form of a quadratic equation, which is y = a(x - h)² + k, where (h, k) is the vertex of the parabola.

Since we know the vertex is at (9, 9), we have h = 9 and k = 9, and the given “a” value is -13. Substituting these into the vertex form, we get:

y = -13(x - 9)² + 9

Expanding this, we obtain:

y = -13(x² - 18x + 81) + 9

Now, distribute the -13:

y = -13x² + 234x - 1053 + 9

Combine like terms to find the value of b and c:

y = -13x² + 234x - 1044

So, b = 234 and c = -1044.

User Colin Humber
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