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Last week, george spent 1 ⅝ hours at the dog park with his dog, gus. this week, he spent 4/6 hours at the dog park with gus. how many more hours did he spend at the dog park last week than this week?

User Grantespo
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1 Answer

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Final answer:

George spent 23/24 hours more at the dog park last week than he did this week after converting both times to a common denominator and subtracting this week's time from last week's time.

Step-by-step explanation:

The question asks us to compare the time George spent at the dog park over two different weeks and find how much longer he spent there last week compared to this week. Last week, he spent 1 ⅛ hours, which is equal to 1 · 8/8 + 5/8, or 13/8 hours when expressed as an improper fraction. This week, he spent 4/6 hours at the dog park. To compare these two amounts of time, we can convert 4/6 to an improper fraction with a denominator of 8 for easy subtraction, which gives us 4/6 · 4/4 = 16/24 = 2/3 · 8/8 = 16/24 = 8/12 = 2/3 · 4/4 = 8/12. Now, we subtract the time spent this week from last week's time:

Last week's time - This week's time = 13/8 hours - 8/12 hours

We need to have a common denominator to subtract these fractions, so we'll use 24 since it's the lowest common multiple of 8 and 12:

13/8 · 3/3 = 39/24 hours

8/12 · 2/2 = 16/24 hours

Now, we can subtract the two:

39/24 hours - 16/24 hours = 23/24 hours

Therefore, George spent 23/24 hours more at the dog park last week than he did this week.

User Amin Merati
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