Question

Khp is often used as a primary standard in acid based titrations if 19.5ml naoh is required to neutralize 0.412g khp, what is the concentration of naoh

Answer 1

The concentration of NaOH is 0.1034 M.

Step-by-step explanation:

To determine the concentration of NaOH, we can use the equation:

KHP (aq) + NaOH (aq) → NaKP (aq) + H2O (l)

Given that 19.5 mL of NaOH is required to neutralize 0.412 g of KHP, we can calculate the molarity of NaOH using the formula:

Molarity (M) = moles of solute / volume of solution (L)

First, we need to convert grams of KHP to moles using its molar mass (204.22 g/mol):

Moles of KHP = 0.412 g / 204.22 g/mol = 0.0020154 mol

Then, we can calculate the molarity of NaOH:

Concentration of NaOH = Moles of NaOH / Volume of NaOH (L)

Concentration of NaOH = 0.0020154 mol / 0.0195 L = 0.1034 M