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It takes 8400j of energy to raise the temperature of 0.5kg of water by 4⁰c. what is the specific heat capacity of water?

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Final answer:

The specific heat capacity of water is calculated using the formula Q = mcΔT. Given the energy supplied (Q), the mass of water (m), and temperature change (ΔT), the specific heat capacity is found to be approximately 4.2 J/g°C.

Step-by-step explanation:

The student was asked to calculate the specific heat capacity of water with given data. The formula to calculate specific heat capacity, c, is Q = mcΔT, where Q is the heat energy supplied, m is the mass of the substance, and ΔT is the temperature change.

From the question, we are given that Q = 8400 J, m = 0.5 kg (which is equal to 500 g since 1 kg = 1000 g), and ΔT = 4°C. Plugging these values into the equation, we get:

8400 J = 500 g * c * 4°C

To find the specific heat capacity, c, we rearrange the formula:

c = 8400 J / (500 g * 4°C)

c = 8400 J / 2000 g°C

c = 4.2 J/g°C

Therefore, the specific heat capacity of water is approximately 4.2 J/g°C.

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