Question

Jc's age is 3 years mroe than sandy's age. joel's age is 1 year less than twice sandy's age. if the product of their ages is 360, how old are they?

Answer 1

By defining Sandy's age as 's', we created relationships for JC and Joel's ages. After setting up the equation for the product of their ages, which is 360, and solving it, we found that Sandy is 5 years old, JC is 8, and Joel is 9 years old.

Step-by-step explanation:

We're asked to solve a problem involving ages and their relationships to one another. Specifically, we have three people: JC, Sandy, and Joel. Their ages are algebraically related as follows:

• JC's age = Sandy's age + 3 years

• Joel's age = 2 × (Sandy's age) - 1 year

The product of their ages is given as 360. Let's denote Sandy's age as 's'. Then JC's age will be 's + 3' and Joel's age will be '2s - 1'.

The equation we get from the product of their ages is:

s × (s + 3) × (2s - 1) = 360

To solve this, we must factor and search for a set of ages (positive integers) that satisfy the equation. After some trial and error, we find that:

• Sandy's age is 5 years

• JC's age is 5 + 3 = 8 years

• Joel's age is 2 × 5 - 1 = 9 years

We verify this solution:

5 × 8 × 9 = 360

Thus, Sandy is 5 years old, JC is 8 years old, and Joel is 9 years old.