Final answer:
0.425 mol of N₂ reacted to produce 0.85 mol of NH₃, based on the stoichiometry of the balanced chemical equation for the formation of ammonia from nitrogen and hydrogen.
Step-by-step explanation:
The student is asking about the number of moles of N₂ that reacted to produce 0.85 mol of NH₃. This question involves understanding the stoichiometry of the chemical reaction between nitrogen (N₂) and hydrogen (H₂) to form ammonia (NH₃), represented by the balanced chemical equation: N₂ (g) + 3H₂ (g) → 2NH₃ (g).
From the balanced equation, we can see that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃. This gives us a mole ratio of 1:2 for N₂ to NH₃. Since we are given that 0.85 mol of NH₃ is produced, we can use this ratio to find the amount of N₂ that reacted:
0.85 mol NH₃ × (1 mol N₂ / 2 mol NH₃) = 0.425 mol N₂
Therefore, 0.425 mol of N₂ reacted to produce 0.85 mol of NH₃.