Final answer:
To determine the number of atoms of oxygen (O) in 75.4 grams of Al(C₂H₃O₂)₃, calculate the molar mass of Al(C₂H₃O₂)₃, convert grams to moles, and then multiply by Avogadro's number.
Step-by-step explanation:
To determine the number of atoms of oxygen (O) in 75.4 grams of Al(C₂H₃O₂)₃, we need to calculate the number of moles of Al(C₂H₃O₂)₃ and then multiply it by the number of atoms of O in one mole.
First, we calculate the molar mass of Al(C₂H₃O₂)₃:
Molar mass of Al(C₂H₃O₂)₃ = (1 x molar mass of Al) + (3 x molar mass of C₂H₃O₂)
Next, we calculate the number of moles of Al(C₂H₃O₂)₃ using the equation:
Number of moles = Mass / Molar mass
Finally, we multiply the number of moles of Al(C₂H₃O₂)₃ by the number of atoms of O in one mole to get the number of atoms of O in 75.4 grams of Al(C₂H₃O₂)₃.