2.1k views
1 vote
Solve and find the two solutions.
3|x+4|-8>=1

User Timigen
by
8.3k points

1 Answer

3 votes

Final answer:

To solve the inequality 3|x+4|-8≥1, we split into two cases based on the absolute value. Case 1 yields x ≥ -1, and Case 2 yields x ≤ -7. The solution set is the union of both cases.

Step-by-step explanation:

To solve the inequality 3|x+4|-8≥1, we must consider the two cases for the absolute value function.

Case 1: x + 4 ≥0

In this case, |x+4| = x + 4. Our inequality becomes:

3(x + 4) - 8 ≥ 1

3x + 12 - 8 ≥ 1

3x + 4 ≥ 1

3x ≥ -3

x ≥ -1

Case 2: x + 4 < 0

In this case, |x+4| = -(x + 4). Our inequality becomes:

3(-x - 4) - 8 ≥ 1

-3x - 12 - 8 ≥ 1

-3x - 20 ≥ 1

-3x ≥ 21

x ≤ -7

Combining the two cases, our solution set is x ≥ -1 or x ≤ -7.

User Uzhas
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories