Question

Solve the triangle. Given: A = 52∘, , b = 14, , c = 6

Answer 1

To solve side a of the triangle, we can use the Law of Cosines. Therefore, side a is approximately 12.67.

To solve the triangle, we can use the Law of Cosines. This states that:

`c^2 = a^2 + b^2`- 2abcos(C), where a, b, and c are the lengths of the sides and C is the angle opposite side c.

In this case, we are given angle A = 52°, side b = 14, and side c = 6. To find side a, we can use the equation:

`a^2 = b^2 + c^2` - 2bccos(A).

Plugging in the values, we get:

`a^2 = 14^2 + 6^2` - 2(14)(6)cos(52°).

`a^2 = 14^2 + 6^2`-168cos(52)

a=
`√(14^2 + 6^2-168sin(52))`

Solving for a, we find a ≈ 12.67.

The probable question may be:"Solve side a the triangle. Given: A = 52∘, , b = 14, , c = 6"