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What is the remainder when 4x3+3x2−38x+38 is divided by x+3?

A) 4x−9
B) 5x−5
C) x−2
D) 11x−5

1 Answer

4 votes

Final Answer:

The remainder when
\(4x^3 + 3x^2 - 38x + 38\) is divided by
\(x + 3\) is
\(5x - 5\). Option B.

Step-by-step explanation:

Polynomial division involves dividing the given polynomial by the divisor and finding the remainder. In this case, when
\(4x^3 + 3x^2 - 38x + 38\) is divided by
\(x + 3\), the remainder is
\(5x - 5\). To determine this, we use the Remainder Theorem, which states that the remainder of a polynomial division can be found by substituting the root of the divisor (in this case,
\(-3\)) into the polynomial.

By substituting
\(-3\) into the given polynomial, we find that the remainder is
\(5(-3) - 5\), which simplifies to
\(-15 - 5\), resulting in
\(-20\). This remainder can be expressed as
\(5x - 5\), which is the correct answer.

Understanding the Remainder Theorem is crucial in polynomial division as it provides a method to find the remainder without fully carrying out the division. It streamlines the process, making it more efficient to determine the remainder when a polynomial is divided by a linear factor.

In summary, the correct answer is
\(5x - 5\) as the remainder when
\(4x^3 + 3x^2 - 38x + 38\) is divided by
\(x + 3\).

User Yorkwar
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