Question

How many moles of SO₃ will be formed when reacting with 2.7 mol of O₂ according to the following reaction?

2SO₂(g) + O₂(g) → 2SO₃(g)

How many moles of SO₃ are formed?

A. 2.7 mol
B. 5.4 mol
C. 1.35 mol
D. 2.25 mol

Answer 1

The number of moles of SO3 formed when reacting with 2.7 mol of O2 is 5.4 mol, according to the stoichiometry of the balanced chemical reaction.

Step-by-step explanation:

To determine how many moles of SO3 are formed when reacting with 2.7 mol of O2, we use the balanced chemical reaction:

2SO2(g) + O2(g) → 2SO3(g)

According to the stoichiometry of the reaction, 1 mole of O2 reacts to form 2 moles of SO3. Therefore, if we have 2.7 moles of O2, it would produce twice that amount in moles of SO3, because the mole ratio between O2 and SO3 is 1:2.

So, the calculation is as follows:

2.7 mol O2 * 2 mol SO3 / 1 mol O2 = 5.4 mol of SO3

The correct answer is B. 5.4 mol